1457261769113 has 4 divisors (see below), whose sum is σ = 1468736271360. Its totient is φ = 1445787266868.

The previous prime is 1457261769107. The next prime is 1457261769167. The reversal of 1457261769113 is 3119671627541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1457261769113 - 2⁴ = 1457261769097 is a prime.

It is a super-2 number, since 2×1457261769113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1457261769913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5737250933 + ... + 5737251186.

It is an arithmetic number, because the mean of its divisors is an integer number (367184067840).

Almost surely, 2^{1457261769113} is an apocalyptic number.

It is an amenable number.

1457261769113 is a deficient number, since it is larger than the sum of its proper divisors (11474502247).

1457261769113 is a wasteful number, since it uses less digits than its factorization.

1457261769113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11474502246.

The product of its digits is 1905120, while the sum is 53.

The spelling of 1457261769113 in words is "one trillion, four hundred fifty-seven billion, two hundred sixty-one million, seven hundred sixty-nine thousand, one hundred thirteen".