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14579318321213 = 139104887182167
BaseRepresentation
bin1101010000101000001100…
…0101101111000000111101
31220121202202202112212111112
43110022003011233000331
53402331420442234323
651001351341131405
73033215046005012
oct324120305570075
956552682485445
1014579318321213
114711066123868
1217756a0259b65
13819a92c106a9
143858ddaa1709
151a439524b178
hexd428316f03d

14579318321213 has 4 divisors (see below), whose sum is σ = 14684205503520. Its totient is φ = 14474431138908.

The previous prime is 14579318321201. The next prime is 14579318321251. The reversal of 14579318321213 is 31212381397541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14579318321213 - 212 = 14579318317117 is a prime.

It is a super-2 number, since 2×145793183212132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14579318321273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52443590945 + ... + 52443591222.

It is an arithmetic number, because the mean of its divisors is an integer number (3671051375880).

Almost surely, 214579318321213 is an apocalyptic number.

It is an amenable number.

14579318321213 is a deficient number, since it is larger than the sum of its proper divisors (104887182307).

14579318321213 is a wasteful number, since it uses less digits than its factorization.

14579318321213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104887182306.

The product of its digits is 1088640, while the sum is 50.

The spelling of 14579318321213 in words is "fourteen trillion, five hundred seventy-nine billion, three hundred eighteen million, three hundred twenty-one thousand, two hundred thirteen".

Divisors: 1 139 104887182167 14579318321213