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14580851592113 = 19379752404747
BaseRepresentation
bin1101010000101101111001…
…1110101100101110110001
31220121220201121200002202122
43110023132132230232301
53402343041001421423
651002203432324025
73033301044413402
oct324133636545661
956556647602678
1014580851592113
1147117826689a4
121775a49843615
13819c78781691
14385a075859a9
151a4434b688c8
hexd42de7acbb1

14580851592113 has 4 divisors (see below), whose sum is σ = 14581604016240. Its totient is φ = 14580099167988.

The previous prime is 14580851592107. The next prime is 14580851592157. The reversal of 14580851592113 is 31129515808541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14580851592113 - 220 = 14580850543537 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14580851592913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376182995 + ... + 376221752.

It is an arithmetic number, because the mean of its divisors is an integer number (3645401004060).

Almost surely, 214580851592113 is an apocalyptic number.

It is an amenable number.

14580851592113 is a deficient number, since it is larger than the sum of its proper divisors (752424127).

14580851592113 is an equidigital number, since it uses as much as digits as its factorization.

14580851592113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 752424126.

The product of its (nonzero) digits is 1728000, while the sum is 53.

The spelling of 14580851592113 in words is "fourteen trillion, five hundred eighty billion, eight hundred fifty-one million, five hundred ninety-two thousand, one hundred thirteen".

Divisors: 1 19379 752404747 14580851592113