14623211140237 has 6 divisors (see below), whose sum is σ = 17010674183598. Its totient is φ = 12534180977304.

The previous prime is 14623211140201. The next prime is 14623211140301. The reversal of 14623211140237 is 73204111232641.

It can be written as a sum of positive squares in only one way, i.e., 10525780967716 + 4097430172521 = 3244346^2 + 2024211^2 .

It is a de Polignac number, because none of the positive numbers 2^k-14623211140237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14623211140196 and 14623211140205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14623211170237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 149216440158 + ... + 149216440255.

It is an arithmetic number, because the mean of its divisors is an integer number (2835112363933).

Almost surely, 2^{14623211140237} is an apocalyptic number.

It is an amenable number.

14623211140237 is a deficient number, since it is larger than the sum of its proper divisors (2387463043361).

14623211140237 is an equidigital number, since it uses as much as digits as its factorization.

14623211140237 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 298432880427 (or 298432880420 counting only the distinct ones).

The product of its (nonzero) digits is 48384, while the sum is 37.

Adding to 14623211140237 its reverse (73204111232641), we get a palindrome (87827322372878).

The spelling of 14623211140237 in words is "fourteen trillion, six hundred twenty-three billion, two hundred eleven million, one hundred forty thousand, two hundred thirty-seven".