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1464242070535 = 5292848414107
BaseRepresentation
bin10101010011101011101…
…000001110010000000111
312011222110112210010000121
4111103223220032100013
5142442231432224120
63040355153122411
7210534166146226
oct25235350162007
95158415703017
101464242070535
11514a88526772
121b7943859407
13a810117cb6a
1450c26626cbd
152814d0025aa
hex154eba0e407

1464242070535 has 4 divisors (see below), whose sum is σ = 1757090484648. Its totient is φ = 1171393656424.

The previous prime is 1464242070503. The next prime is 1464242070569. The reversal of 1464242070535 is 5350702424641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1464242070535 - 25 = 1464242070503 is a prime.

It is a super-2 number, since 2×14642420705352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1464242070491 and 1464242070500.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146424207049 + ... + 146424207058.

It is an arithmetic number, because the mean of its divisors is an integer number (439272621162).

Almost surely, 21464242070535 is an apocalyptic number.

1464242070535 is a deficient number, since it is larger than the sum of its proper divisors (292848414113).

1464242070535 is an equidigital number, since it uses as much as digits as its factorization.

1464242070535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292848414112.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 1464242070535 in words is "one trillion, four hundred sixty-four billion, two hundred forty-two million, seventy thousand, five hundred thirty-five".

Divisors: 1 5 292848414107 1464242070535