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14650485191311 = 105113939567261
BaseRepresentation
bin1101010100110001010011…
…1101110011001010001111
31220212120110111120110020011
43111030110331303022033
53410013143202110221
651054201234134051
73041314452300214
oct325142475631217
956776414513204
1014650485191311
114739265a53692
121787441a21327
138236c501ca08
14389131661b0b
151a615d0011e1
hexd5314f7328f

14650485191311 has 4 divisors (see below), whose sum is σ = 14664424759624. Its totient is φ = 14636545623000.

The previous prime is 14650485191269. The next prime is 14650485191339. The reversal of 14650485191311 is 11319158405641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14650485191311 - 219 = 14650484667023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14650485194311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6969782580 + ... + 6969784681.

It is an arithmetic number, because the mean of its divisors is an integer number (3666106189906).

Almost surely, 214650485191311 is an apocalyptic number.

14650485191311 is a deficient number, since it is larger than the sum of its proper divisors (13939568313).

14650485191311 is a wasteful number, since it uses less digits than its factorization.

14650485191311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13939568312.

The product of its (nonzero) digits is 518400, while the sum is 49.

The spelling of 14650485191311 in words is "fourteen trillion, six hundred fifty billion, four hundred eighty-five million, one hundred ninety-one thousand, three hundred eleven".

Divisors: 1 1051 13939567261 14650485191311