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1466142015997 = 1977165369263
BaseRepresentation
bin10101010101011100110…
…111111100000111111101
312012011100221212100020001
4111111130313330013331
5143010124324002442
63041311503354301
7210632236340641
oct25253467740775
95164327770201
101466142015997
11515872a4492a
121b8193bb2991
13a8344994949
1450d66ab8c21
152820ebee2b7
hex1555cdfc1fd

1466142015997 has 4 divisors (see below), whose sum is σ = 1543307385280. Its totient is φ = 1388976646716.

The previous prime is 1466142015991. The next prime is 1466142016067. The reversal of 1466142015997 is 7995102416641.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1466142015997 - 211 = 1466142013949 is a prime.

It is a super-2 number, since 2×14661420159972 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1466142015991) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38582684613 + ... + 38582684650.

It is an arithmetic number, because the mean of its divisors is an integer number (385826846320).

Almost surely, 21466142015997 is an apocalyptic number.

It is an amenable number.

1466142015997 is a deficient number, since it is larger than the sum of its proper divisors (77165369283).

1466142015997 is an equidigital number, since it uses as much as digits as its factorization.

1466142015997 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77165369282.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 1466142015997 in words is "one trillion, four hundred sixty-six billion, one hundred forty-two million, fifteen thousand, nine hundred ninety-seven".

Divisors: 1 19 77165369263 1466142015997