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146741554700047 = 151971798375497
BaseRepresentation
bin100001010111010111101110…
…001111011101111100001111
3201020120100121020202222021001
4201113113232033131330033
5123213203201000400142
61240032050052521131
742623504343533626
oct4127275617357417
9636510536688231
10146741554700047
11428358200a14aa
121455b5b59201a7
1363b58913c4728
1428344872506bd
1511e71407655b7
hex8575ee3ddf0f

146741554700047 has 4 divisors (see below), whose sum is σ = 147713353075696. Its totient is φ = 145769756324400.

The previous prime is 146741554700029. The next prime is 146741554700051. The reversal of 146741554700047 is 740007455147641.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-146741554700047 is a prime.

It is a super-2 number, since 2×1467415547000472 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (146741554700747) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 485899187598 + ... + 485899187899.

It is an arithmetic number, because the mean of its divisors is an integer number (36928338268924).

Almost surely, 2146741554700047 is an apocalyptic number.

146741554700047 is a deficient number, since it is larger than the sum of its proper divisors (971798375649).

146741554700047 is an equidigital number, since it uses as much as digits as its factorization.

146741554700047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 971798375648.

The product of its (nonzero) digits is 13171200, while the sum is 55.

The spelling of 146741554700047 in words is "one hundred forty-six trillion, seven hundred forty-one billion, five hundred fifty-four million, seven hundred thousand, forty-seven".

Divisors: 1 151 971798375497 146741554700047