Base | Representation |
---|---|
bin | 10101010111010011110… |
… | …111001110101100110010 |
3 | 12012100112002021000122001 |
4 | 111113103313032230302 |
5 | 143023221402144032 |
6 | 3042241535204214 |
7 | 211032556543162 |
oct | 25272367165462 |
9 | 5170462230561 |
10 | 1468138318642 |
11 | 5166a7896626 |
12 | 1b865067666a |
13 | a85a2446108 |
14 | 510b5c905a2 |
15 | 282ca0d13e7 |
hex | 155d3dceb32 |
1468138318642 has 4 divisors (see below), whose sum is σ = 2202207477966. Its totient is φ = 734069159320.
The previous prime is 1468138318601. The next prime is 1468138318643. The reversal of 1468138318642 is 2468138318641.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1245034187721 + 223104130921 = 1115811^2 + 472339^2 .
It is not an unprimeable number, because it can be changed into a prime (1468138318643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 367034579659 + ... + 367034579662.
Almost surely, 21468138318642 is an apocalyptic number.
1468138318642 is a deficient number, since it is larger than the sum of its proper divisors (734069159324).
1468138318642 is an equidigital number, since it uses as much as digits as its factorization.
1468138318642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 734069159323.
The product of its digits is 5308416, while the sum is 55.
Subtracting 1468138318642 from its reverse (2468138318641), we obtain a palindrome (999999999999).
The spelling of 1468138318642 in words is "one trillion, four hundred sixty-eight billion, one hundred thirty-eight million, three hundred eighteen thousand, six hundred forty-two".
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