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147004344138 = 2347951149737
BaseRepresentation
bin1000100011101000100…
…1000100011101001010
3112001102222121102120110
42020322021010131022
54402031103003023
6151311033135150
713422622210461
oct2107211043512
9461388542513
10147004344138
1157387135603
12245a755a4b6
1310b29a59322
1471879999d8
153c55ae7a93
hex223a24474a

147004344138 has 16 divisors (see below), whose sum is σ = 294622490880. Its totient is φ = 48899147616.

The previous prime is 147004344133. The next prime is 147004344173. The reversal of 147004344138 is 831443400741.

It is a super-2 number, since 2×1470043441382 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 147004344096 and 147004344105.

It is not an unprimeable number, because it can be changed into a prime (147004344133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25571995 + ... + 25577742.

It is an arithmetic number, because the mean of its divisors is an integer number (18413905680).

Almost surely, 2147004344138 is an apocalyptic number.

147004344138 is an abundant number, since it is smaller than the sum of its proper divisors (147618146742).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

147004344138 is a wasteful number, since it uses less digits than its factorization.

147004344138 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51150221.

The product of its (nonzero) digits is 129024, while the sum is 39.

Adding to 147004344138 its reverse (831443400741), we get a palindrome (978447744879).

The spelling of 147004344138 in words is "one hundred forty-seven billion, four million, three hundred forty-four thousand, one hundred thirty-eight".

Divisors: 1 2 3 6 479 958 1437 2874 51149737 102299474 153449211 306898422 24500724023 49001448046 73502172069 147004344138