Search a number
-
+
1473360540243 = 3491120180081
BaseRepresentation
bin10101011100001011001…
…000011011001001010011
312012212000000210100220220
4111130023020123021103
5143114420244241433
63044504045404123
7211306150646064
oct25341310331123
95185000710826
101473360540243
11518937683a49
121b9669569643
13a8c2533c677
145144d67a56b
15284d37d12b3
hex1570b21b253

1473360540243 has 4 divisors (see below), whose sum is σ = 1964480720328. Its totient is φ = 982240360160.

The previous prime is 1473360540233. The next prime is 1473360540269. The reversal of 1473360540243 is 3420450633741.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1473360540243 - 230 = 1472286798419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1473360540195 and 1473360540204.

It is not an unprimeable number, because it can be changed into a prime (1473360540233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245560090038 + ... + 245560090043.

It is an arithmetic number, because the mean of its divisors is an integer number (491120180082).

Almost surely, 21473360540243 is an apocalyptic number.

1473360540243 is a deficient number, since it is larger than the sum of its proper divisors (491120180085).

1473360540243 is an equidigital number, since it uses as much as digits as its factorization.

1473360540243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491120180084.

The product of its (nonzero) digits is 725760, while the sum is 42.

The spelling of 1473360540243 in words is "one trillion, four hundred seventy-three billion, three hundred sixty million, five hundred forty thousand, two hundred forty-three".

Divisors: 1 3 491120180081 1473360540243