1473653312041 has 4 divisors (see below), whose sum is σ = 1513481779972. Its totient is φ = 1433824844112.

The previous prime is 1473653311973. The next prime is 1473653312063. The reversal of 1473653312041 is 1402133563741.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1077452304016 + 396201008025 = 1038004^2 + 629445^2 .

It is a cyclic number.

It is not a de Polignac number, because 1473653312041 - 2¹³ = 1473653303849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1473653311985 and 1473653312003.

It is not an unprimeable number, because it can be changed into a prime (1473653312081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19914233910 + ... + 19914233983.

It is an arithmetic number, because the mean of its divisors is an integer number (378370444993).

Almost surely, 2^{1473653312041} is an apocalyptic number.

It is an amenable number.

1473653312041 is a deficient number, since it is larger than the sum of its proper divisors (39828467931).

1473653312041 is an equidigital number, since it uses as much as digits as its factorization.

1473653312041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39828467930.

The product of its (nonzero) digits is 181440, while the sum is 40.

Adding to 1473653312041 its reverse (1402133563741), we get a palindrome (2875786875782).

The spelling of 1473653312041 in words is "one trillion, four hundred seventy-three billion, six hundred fifty-three million, three hundred twelve thousand, forty-one".