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1474113342035 = 51092704795123
BaseRepresentation
bin10101011100111000000…
…000001000101001010011
312012220221111022122211202
4111130320000020221103
5143122441003421120
63045110500501415
7211333621444355
oct25347000105123
95186844278752
101474113342035
11519193608094
121b98396aa86b
13a90152a8509
14514c163b0d5
1528529933875
hex15738008a53

1474113342035 has 8 divisors (see below), whose sum is σ = 1785164781840. Its totient is φ = 1168471492704.

The previous prime is 1474113342029. The next prime is 1474113342059. The reversal of 1474113342035 is 5302433114741.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1474113342035 - 210 = 1474113341011 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1474113342035.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1352397017 + ... + 1352398106.

It is an arithmetic number, because the mean of its divisors is an integer number (223145597730).

Almost surely, 21474113342035 is an apocalyptic number.

1474113342035 is a deficient number, since it is larger than the sum of its proper divisors (311051439805).

1474113342035 is a wasteful number, since it uses less digits than its factorization.

1474113342035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2704795237.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 1474113342035 its reverse (5302433114741), we get a palindrome (6776546456776).

The spelling of 1474113342035 in words is "one trillion, four hundred seventy-four billion, one hundred thirteen million, three hundred forty-two thousand, thirty-five".

Divisors: 1 5 109 545 2704795123 13523975615 294822668407 1474113342035