Base | Representation |
---|---|
bin | 1000101000101101001… |
… | …0100111011110001001 |
3 | 112011221212102121202202 |
4 | 2022023102213132021 |
5 | 4412323121120403 |
6 | 152054110005545 |
7 | 13501433334500 |
oct | 2121322473611 |
9 | 464855377682 |
10 | 148365801353 |
11 | 57a15699560 |
12 | 249074a68b5 |
13 | 10cb5b31603 |
14 | 7276717837 |
15 | 3cd53c7688 |
hex | 228b4a7789 |
148365801353 has 48 divisors (see below), whose sum is σ = 198505117440. Its totient is φ = 109349805600.
The previous prime is 148365801329. The next prime is 148365801361. The reversal of 148365801353 is 353108563841.
It is not a de Polignac number, because 148365801353 - 226 = 148298692489 is a prime.
It is a super-2 number, since 2×1483658013532 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 148365801298 and 148365801307.
It is not an unprimeable number, because it can be changed into a prime (148365801053) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6573698 + ... + 6596228.
It is an arithmetic number, because the mean of its divisors is an integer number (4135523280).
Almost surely, 2148365801353 is an apocalyptic number.
It is an amenable number.
148365801353 is a deficient number, since it is larger than the sum of its proper divisors (50139316087).
148365801353 is a wasteful number, since it uses less digits than its factorization.
148365801353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23218 (or 23211 counting only the distinct ones).
The product of its (nonzero) digits is 1036800, while the sum is 47.
The spelling of 148365801353 in words is "one hundred forty-eight billion, three hundred sixty-five million, eight hundred one thousand, three hundred fifty-three".
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