14853282481351 has 4 divisors (see below), whose sum is σ = 15727004980272. Its totient is φ = 13979559982432.

The previous prime is 14853282481321. The next prime is 14853282481357. The reversal of 14853282481351 is 15318428235841.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14853282481351 - 2⁵ = 14853282481319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14853282481292 and 14853282481301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14853282481357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 436861249435 + ... + 436861249468.

It is an arithmetic number, because the mean of its divisors is an integer number (3931751245068).

Almost surely, 2^{14853282481351} is an apocalyptic number.

14853282481351 is a deficient number, since it is larger than the sum of its proper divisors (873722498921).

14853282481351 is an equidigital number, since it uses as much as digits as its factorization.

14853282481351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 873722498920.

The product of its digits is 7372800, while the sum is 55.

The spelling of 14853282481351 in words is "fourteen trillion, eight hundred fifty-three billion, two hundred eighty-two million, four hundred eighty-one thousand, three hundred fifty-one".