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14860129947 = 3132171724113
BaseRepresentation
bin11011101011011101…
…11001011010011011
31102100121221211001020
431311232321122123
5220413143124242
610454320053523
71034151010005
oct156556713233
942317854036
1014860129947
116336179633
122a687642a3
13152a885c00
14a0d815375
155be8d66ec
hex375bb969b

14860129947 has 24 divisors (see below), whose sum is σ = 22716926064. Its totient is φ = 8606767104.

The previous prime is 14860129939. The next prime is 14860129951. The reversal of 14860129947 is 74992106841.

It is not a de Polignac number, because 14860129947 - 23 = 14860129939 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is a self number, because there is not a number n which added to its sum of digits gives 14860129947.

It is not an unprimeable number, because it can be changed into a prime (14860129927) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 853438 + ... + 870675.

It is an arithmetic number, because the mean of its divisors is an integer number (946538586).

Almost surely, 214860129947 is an apocalyptic number.

14860129947 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

14860129947 is a deficient number, since it is larger than the sum of its proper divisors (7856796117).

14860129947 is a wasteful number, since it uses less digits than its factorization.

14860129947 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1724159 (or 1724146 counting only the distinct ones).

The product of its (nonzero) digits is 870912, while the sum is 51.

The spelling of 14860129947 in words is "fourteen billion, eight hundred sixty million, one hundred twenty-nine thousand, nine hundred forty-seven".

Divisors: 1 3 13 17 39 51 169 221 507 663 2873 8619 1724113 5172339 22413469 29309921 67240407 87929763 291375097 381028973 874125291 1143086919 4953376649 14860129947