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1490919949103 = 13114686149931
BaseRepresentation
bin10101101100100001110…
…000010000001100101111
312021112022202220202112012
4111230201300100030233
5143411401001332403
63100530312431435
7212500246316654
oct25544160201457
95245282822465
101490919949103
115253284967a2
12200b4a0a857b
13aa7931b8a20
1452237777c2b
1528bb0158ed8
hex15b21c1032f

1490919949103 has 4 divisors (see below), whose sum is σ = 1605606099048. Its totient is φ = 1376233799160.

The previous prime is 1490919949049. The next prime is 1490919949147. The reversal of 1490919949103 is 3019499190941.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1490919949103 - 210 = 1490919948079 is a prime.

It is a super-2 number, since 2×14909199491032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1490919949403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57343074953 + ... + 57343074978.

It is an arithmetic number, because the mean of its divisors is an integer number (401401524762).

Almost surely, 21490919949103 is an apocalyptic number.

1490919949103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1490919949103 is a deficient number, since it is larger than the sum of its proper divisors (114686149945).

1490919949103 is a wasteful number, since it uses less digits than its factorization.

1490919949103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114686149944.

The product of its (nonzero) digits is 2834352, while the sum is 59.

The spelling of 1490919949103 in words is "one trillion, four hundred ninety billion, nine hundred nineteen million, nine hundred forty-nine thousand, one hundred three".

Divisors: 1 13 114686149931 1490919949103