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149141019840 = 26351931263761
BaseRepresentation
bin1000101011100101111…
…1110101110011000000
3112020221220010210121120
42022321133311303000
54420420100113330
6152303041352240
713526565515631
oct2127137656300
9466856123546
10149141019840
115828324369a
1224aa3038680
13110aa618887
14730b671888
153d2d4a6c10
hex22b97f5cc0

149141019840 has 224 divisors, whose sum is σ = 514525808640. Its totient is φ = 36462182400.

The previous prime is 149141019829. The next prime is 149141019847. The reversal of 149141019840 is 48910141941.

It is a junction number, because it is equal to n+sod(n) for n = 149141019792 and 149141019801.

It is not an unprimeable number, because it can be changed into a prime (149141019847) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 433560 + ... + 697320.

Almost surely, 2149141019840 is an apocalyptic number.

149141019840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 149141019840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (257262904320).

149141019840 is an abundant number, since it is smaller than the sum of its proper divisors (365384788800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

149141019840 is a wasteful number, since it uses less digits than its factorization.

149141019840 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263831 (or 263821 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 42.

The spelling of 149141019840 in words is "one hundred forty-nine billion, one hundred forty-one million, nineteen thousand, eight hundred forty".