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1492025292055 = 5298405058411
BaseRepresentation
bin10101101101100011101…
…000110011010100010111
312021122011210211000000001
4111231203220303110113
5143421131433321210
63101232120032131
7212536530505114
oct25554350632427
95248153730001
101492025292055
11525845420271
122011b8302647
13aa90b1ba5cc
14523004a790b
1528c271e803a
hex15b63a33517

1492025292055 has 4 divisors (see below), whose sum is σ = 1790430350472. Its totient is φ = 1193620233640.

The previous prime is 1492025292047. The next prime is 1492025292077. The reversal of 1492025292055 is 5502925202941.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1492025292055 - 23 = 1492025292047 is a prime.

It is a super-2 number, since 2×14920252920552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1492025291996 and 1492025292014.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149202529201 + ... + 149202529210.

It is an arithmetic number, because the mean of its divisors is an integer number (447607587618).

Almost surely, 21492025292055 is an apocalyptic number.

1492025292055 is a deficient number, since it is larger than the sum of its proper divisors (298405058417).

1492025292055 is an equidigital number, since it uses as much as digits as its factorization.

1492025292055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298405058416.

The product of its (nonzero) digits is 648000, while the sum is 46.

The spelling of 1492025292055 in words is "one trillion, four hundred ninety-two billion, twenty-five million, two hundred ninety-two thousand, fifty-five".

Divisors: 1 5 298405058411 1492025292055