149271813053 has 4 divisors (see below), whose sum is σ = 162841977888. Its totient is φ = 135701648220.

The previous prime is 149271813049. The next prime is 149271813077. The reversal of 149271813053 is 350318172941.

149271813053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 350318172941 = 11 ⋅31847106631.

It is a cyclic number.

It is not a de Polignac number, because 149271813053 - 2² = 149271813049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 149271812995 and 149271813013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (149271813853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6785082401 + ... + 6785082422.

It is an arithmetic number, because the mean of its divisors is an integer number (40710494472).

Almost surely, 2^149271813053 is an apocalyptic number.

It is an amenable number.

149271813053 is a deficient number, since it is larger than the sum of its proper divisors (13570164835).

149271813053 is a wasteful number, since it uses less digits than its factorization.

149271813053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13570164834.

The product of its (nonzero) digits is 181440, while the sum is 44.

Adding to 149271813053 its reverse (350318172941), we get a palindrome (499589985994).

The spelling of 149271813053 in words is "one hundred forty-nine billion, two hundred seventy-one million, eight hundred thirteen thousand, fifty-three".