Base | Representation |
---|---|
bin | 11011110100111101… |
… | …00000111011101001 |
3 | 1102120011201111001122 |
4 | 31322132200323221 |
5 | 221044032041244 |
6 | 10510242025025 |
7 | 1036135352132 |
oct | 157236407351 |
9 | 42504644048 |
10 | 14939721449 |
11 | 63770a0934 |
12 | 2a8b348175 |
13 | 1541202383 |
14 | a1a212c89 |
15 | 5c68a91ee |
hex | 37a7a0ee9 |
14939721449 has 4 divisors (see below), whose sum is σ = 15023183760. Its totient is φ = 14856259140.
The previous prime is 14939721443. The next prime is 14939721473. The reversal of 14939721449 is 94412793941.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14939721449 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14939721449.
It is not an unprimeable number, because it can be changed into a prime (14939721443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41730887 + ... + 41731244.
It is an arithmetic number, because the mean of its divisors is an integer number (3755795940).
Almost surely, 214939721449 is an apocalyptic number.
It is an amenable number.
14939721449 is a deficient number, since it is larger than the sum of its proper divisors (83462311).
14939721449 is an equidigital number, since it uses as much as digits as its factorization.
14939721449 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83462310.
The product of its digits is 1959552, while the sum is 53.
The spelling of 14939721449 in words is "fourteen billion, nine hundred thirty-nine million, seven hundred twenty-one thousand, four hundred forty-nine".
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