Base | Representation |
---|---|
bin | 10101101111011000101… |
… | …101110110110001110001 |
3 | 12021211020200220201000101 |
4 | 111233120231312301301 |
5 | 143434142311114332 |
6 | 3102155044552401 |
7 | 212636311441162 |
oct | 25573055666161 |
9 | 5254220821011 |
10 | 1493989551217 |
11 | 526663176249 |
12 | 2016660b2701 |
13 | aab6212c937 |
14 | 524492db769 |
15 | 28cde89aae7 |
hex | 15bd8b76c71 |
1493989551217 has 4 divisors (see below), whose sum is σ = 1494288174960. Its totient is φ = 1493690927476.
The previous prime is 1493989551179. The next prime is 1493989551293. The reversal of 1493989551217 is 7121559893941.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1493989551217 - 215 = 1493989518449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1493989551617) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149304367 + ... + 149314372.
It is an arithmetic number, because the mean of its divisors is an integer number (373572043740).
Almost surely, 21493989551217 is an apocalyptic number.
It is an amenable number.
1493989551217 is a deficient number, since it is larger than the sum of its proper divisors (298623743).
1493989551217 is an equidigital number, since it uses as much as digits as its factorization.
1493989551217 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298623742.
The product of its digits is 24494400, while the sum is 64.
The spelling of 1493989551217 in words is "one trillion, four hundred ninety-three billion, nine hundred eighty-nine million, five hundred fifty-one thousand, two hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •