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14976230051 = 23651140437
BaseRepresentation
bin11011111001010011…
…10010001010100011
31102122201102022110002
431330221302022203
5221132403330201
610514024330215
71040060566166
oct157451621243
942581368402
1014976230051
116395767332
122a9b61396b
1315489459b3
14a20dd7add
155c9bbb76b
hex37ca722a3

14976230051 has 4 divisors (see below), whose sum is σ = 15627370512. Its totient is φ = 14325089592.

The previous prime is 14976230047. The next prime is 14976230063. The reversal of 14976230051 is 15003267941.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15003267941 = 17882545173.

It is a cyclic number.

It is not a de Polignac number, because 14976230051 - 22 = 14976230047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14976229987 and 14976230014.

It is not an unprimeable number, because it can be changed into a prime (14976230011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325570196 + ... + 325570241.

It is an arithmetic number, because the mean of its divisors is an integer number (3906842628).

Almost surely, 214976230051 is an apocalyptic number.

14976230051 is a deficient number, since it is larger than the sum of its proper divisors (651140461).

14976230051 is an equidigital number, since it uses as much as digits as its factorization.

14976230051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 651140460.

The product of its (nonzero) digits is 45360, while the sum is 38.

Adding to 14976230051 its reverse (15003267941), we get a palindrome (29979497992).

The spelling of 14976230051 in words is "fourteen billion, nine hundred seventy-six million, two hundred thirty thousand, fifty-one".

Divisors: 1 23 651140437 14976230051