Base | Representation |
---|---|
bin | 100010000110110011011010… |
… | …111000001101000001100010 |
3 | 201200002222002021011020122012 |
4 | 202012303122320031001202 |
5 | 124130104233130341002 |
6 | 1251005320355312522 |
7 | 43411136224536104 |
oct | 4206633270150142 |
9 | 650088067136565 |
10 | 150001110012002 |
11 | 43882128098757 |
12 | 149a72782ab742 |
13 | 6591075813a52 |
14 | 2908141a03574 |
15 | 1251d16ae1d52 |
hex | 886cdae0d062 |
150001110012002 has 4 divisors (see below), whose sum is σ = 225001665018006. Its totient is φ = 75000555006000.
The previous prime is 150001110011941. The next prime is 150001110012037. The reversal of 150001110012002 is 200210011100051.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 145598033092801 + 4403076919201 = 12066401^2 + 2098351^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37500277502999 + ... + 37500277503002.
Almost surely, 2150001110012002 is an apocalyptic number.
150001110012002 is a deficient number, since it is larger than the sum of its proper divisors (75000555006004).
150001110012002 is an equidigital number, since it uses as much as digits as its factorization.
150001110012002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75000555006003.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 150001110012002 its reverse (200210011100051), we get a palindrome (350211121112053).
The spelling of 150001110012002 in words is "one hundred fifty trillion, one billion, one hundred ten million, twelve thousand, two".
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