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150003132031 = 576532601827
BaseRepresentation
bin1000101110110011100…
…0100010011001111111
3112100011222100122012201
42023230320202121333
54424201300211111
6152524355412331
713560134404354
oct2135470423177
9470158318181
10150003132031
1158685948305
12250a38b40a7
13111b7107c2c
14738dd6862b
153d7deec6c1
hex22ece2267f

150003132031 has 4 divisors (see below), whose sum is σ = 150005791512. Its totient is φ = 150000472552.

The previous prime is 150003132029. The next prime is 150003132121. The reversal of 150003132031 is 130231300051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150003132031 - 21 = 150003132029 is a prime.

It is a super-2 number, since 2×1500031320312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150003132131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1243261 + ... + 1358566.

It is an arithmetic number, because the mean of its divisors is an integer number (37501447878).

Almost surely, 2150003132031 is an apocalyptic number.

150003132031 is a deficient number, since it is larger than the sum of its proper divisors (2659481).

150003132031 is an equidigital number, since it uses as much as digits as its factorization.

150003132031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2659480.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 150003132031 its reverse (130231300051), we get a palindrome (280234432082).

The spelling of 150003132031 in words is "one hundred fifty billion, three million, one hundred thirty-two thousand, thirty-one".

Divisors: 1 57653 2601827 150003132031