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150004334945 = 559508489271
BaseRepresentation
bin1000101110110011110…
…1001000000101100001
3112100012001121202022002
42023230331020011201
54424202102204240
6152524441253345
713560150544403
oct2135475100541
9470161552262
10150004334945
115868659a053
12250a4194255
13111b743960a
14739019cb73
153d7e188d15
hex22ecf48161

150004334945 has 8 divisors (see below), whose sum is σ = 183056137920. Its totient is φ = 117969510640.

The previous prime is 150004334933. The next prime is 150004334951. The reversal of 150004334945 is 549433400051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 150004334945 - 212 = 150004330849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 150004334899 and 150004334908.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 254244341 + ... + 254244930.

It is an arithmetic number, because the mean of its divisors is an integer number (22882017240).

Almost surely, 2150004334945 is an apocalyptic number.

It is an amenable number.

150004334945 is a deficient number, since it is larger than the sum of its proper divisors (33051802975).

150004334945 is an equidigital number, since it uses as much as digits as its factorization.

150004334945 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 508489335.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 150004334945 its reverse (549433400051), we get a palindrome (699437734996).

The spelling of 150004334945 in words is "one hundred fifty billion, four million, three hundred thirty-four thousand, nine hundred forty-five".

Divisors: 1 5 59 295 508489271 2542446355 30000866989 150004334945