150010552541 has 4 divisors (see below), whose sum is σ = 157905844800. Its totient is φ = 142115260284.

The previous prime is 150010552519. The next prime is 150010552547. The reversal of 150010552541 is 145255010051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150010552541 - 2¹⁴ = 150010536157 is a prime.

It is a super-3 number, since 3×150010552541³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150010552547) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3947646101 + ... + 3947646138.

It is an arithmetic number, because the mean of its divisors is an integer number (39476461200).

Almost surely, 2^150010552541 is an apocalyptic number.

It is an amenable number.

150010552541 is a deficient number, since it is larger than the sum of its proper divisors (7895292259).

150010552541 is an equidigital number, since it uses as much as digits as its factorization.

150010552541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7895292258.

The product of its (nonzero) digits is 5000, while the sum is 29.

Adding to 150010552541 its reverse (145255010051), we get a palindrome (295265562592).

The spelling of 150010552541 in words is "one hundred fifty billion, ten million, five hundred fifty-two thousand, five hundred forty-one".