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150010681738 = 275005340869
BaseRepresentation
bin1000101110110101010…
…1010101100110001010
3112100012111120012110111
42023231111111212022
54424210213303423
6152525225304534
713560255520231
oct2135525254612
9470174505414
10150010681738
115868a134535
12250a633514a
13111b884c408
147390d71b18
153d7e9de60d
hex22ed55598a

150010681738 has 4 divisors (see below), whose sum is σ = 225016022610. Its totient is φ = 75005340868.

The previous prime is 150010681729. The next prime is 150010681759. The reversal of 150010681738 is 837186010051.

150010681738 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 135767930089 + 14242751649 = 368467^2 + 119343^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 150010681738.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37502670433 + ... + 37502670436.

Almost surely, 2150010681738 is an apocalyptic number.

150010681738 is a deficient number, since it is larger than the sum of its proper divisors (75005340872).

150010681738 is an equidigital number, since it uses as much as digits as its factorization.

150010681738 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75005340871.

The product of its (nonzero) digits is 40320, while the sum is 40.

Adding to 150010681738 its reverse (837186010051), we get a palindrome (987196691789).

The spelling of 150010681738 in words is "one hundred fifty billion, ten million, six hundred eighty-one thousand, seven hundred thirty-eight".

Divisors: 1 2 75005340869 150010681738