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150013502943 = 3250319977827
BaseRepresentation
bin1000101110110110000…
…0000110010111011111
3112100012200212112102120
42023231200012113133
54424211424043233
6152525405554023
713560321510303
oct2135540062737
9470180775376
10150013502943
1158690791107
12250a7275913
13111b92c9575
1473914a7d03
153d7ed9a4b3
hex22ed8065df

150013502943 has 8 divisors (see below), whose sum is σ = 200097925248. Its totient is φ = 99969041304.

The previous prime is 150013502909. The next prime is 150013502981. The reversal of 150013502943 is 349205310051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 150013502943 - 210 = 150013501919 is a prime.

It is a super-2 number, since 2×1500135029432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150013501943) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9981405 + ... + 9996422.

It is an arithmetic number, because the mean of its divisors is an integer number (25012240656).

Almost surely, 2150013502943 is an apocalyptic number.

150013502943 is a deficient number, since it is larger than the sum of its proper divisors (50084422305).

150013502943 is a wasteful number, since it uses less digits than its factorization.

150013502943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19980333.

The product of its (nonzero) digits is 16200, while the sum is 33.

Adding to 150013502943 its reverse (349205310051), we get a palindrome (499218812994).

The spelling of 150013502943 in words is "one hundred fifty billion, thirteen million, five hundred two thousand, nine hundred forty-three".

Divisors: 1 3 2503 7509 19977827 59933481 50004500981 150013502943