Base | Representation |
---|---|
bin | 1000101110110110001… |
… | …1010110011100001011 |
3 | 112100012202110211112001 |
4 | 2023231203112130023 |
5 | 4424212133331321 |
6 | 152525440131431 |
7 | 13560331660120 |
oct | 2135543263413 |
9 | 470182424461 |
10 | 150014355211 |
11 | 58691213466 |
12 | 250a7606b77 |
13 | 111b9537476 |
14 | 739164a747 |
15 | 3d7eeb7c91 |
hex | 22ed8d670b |
150014355211 has 8 divisors (see below), whose sum is σ = 171835516160. Its totient is φ = 128290828968.
The previous prime is 150014355167. The next prime is 150014355241. The reversal of 150014355211 is 112553410051.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 150014355211 - 215 = 150014322443 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 150014355211.
It is not an unprimeable number, because it can be changed into a prime (150014355241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24405381 + ... + 24411526.
It is an arithmetic number, because the mean of its divisors is an integer number (21479439520).
Almost surely, 2150014355211 is an apocalyptic number.
150014355211 is a deficient number, since it is larger than the sum of its proper divisors (21821160949).
150014355211 is an equidigital number, since it uses as much as digits as its factorization.
150014355211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48817353.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 150014355211 its reverse (112553410051), we get a palindrome (262567765262).
The spelling of 150014355211 in words is "one hundred fifty billion, fourteen million, three hundred fifty-five thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •