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150014355241 is a prime number
BaseRepresentation
bin1000101110110110001…
…1010110011100101001
3112100012202110211120011
42023231203112130221
54424212133331431
6152525440131521
713560331660162
oct2135543263451
9470182424504
10150014355241
1158691213493
12250a7606ba1
13111b953749a
14739164a769
153d7eeb7cb1
hex22ed8d6729

150014355241 has 2 divisors, whose sum is σ = 150014355242. Its totient is φ = 150014355240.

The previous prime is 150014355167. The next prime is 150014355247. The reversal of 150014355241 is 142553410051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100806250000 + 49208105241 = 317500^2 + 221829^2 .

It is a cyclic number.

It is not a de Polignac number, because 150014355241 - 215 = 150014322473 is a prime.

It is not a weakly prime, because it can be changed into another prime (150014355247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75007177620 + 75007177621.

It is an arithmetic number, because the mean of its divisors is an integer number (75007177621).

Almost surely, 2150014355241 is an apocalyptic number.

It is an amenable number.

150014355241 is a deficient number, since it is larger than the sum of its proper divisors (1).

150014355241 is an equidigital number, since it uses as much as digits as its factorization.

150014355241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 150014355241 its reverse (142553410051), we get a palindrome (292567765292).

The spelling of 150014355241 in words is "one hundred fifty billion, fourteen million, three hundred fifty-five thousand, two hundred forty-one".