Base | Representation |
---|---|
bin | 100010000110111111110101… |
… | …101010001011001001101010 |
3 | 201200011020111112211020200222 |
4 | 202012333311222023021222 |
5 | 124130314040210033114 |
6 | 1251015403445530042 |
7 | 43412120526462101 |
oct | 4206776552131152 |
9 | 650136445736628 |
10 | 150014444221034 |
11 | 4388784a992318 |
12 | 149a9979a13922 |
13 | 65923bc200273 |
14 | 2908a488c9038 |
15 | 125234755d98e |
hex | 886ff5a8b26a |
150014444221034 has 4 divisors (see below), whose sum is σ = 225021666331554. Its totient is φ = 75007222110516.
The previous prime is 150014444221013. The next prime is 150014444221051. The reversal of 150014444221034 is 430122444410051.
150014444221034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 128473270506025 + 21541173715009 = 11334605^2 + 4641247^2 .
It is a junction number, because it is equal to n+sod(n) for n = 150014444220985 and 150014444221003.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37503611055257 + ... + 37503611055260.
Almost surely, 2150014444221034 is an apocalyptic number.
150014444221034 is a deficient number, since it is larger than the sum of its proper divisors (75007222110520).
150014444221034 is an equidigital number, since it uses as much as digits as its factorization.
150014444221034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75007222110519.
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 150014444221034 its reverse (430122444410051), we get a palindrome (580136888631085).
The spelling of 150014444221034 in words is "one hundred fifty trillion, fourteen billion, four hundred forty-four million, two hundred twenty-one thousand, thirty-four".
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