Base | Representation |
---|---|
bin | 1000101110110110110… |
… | …1101100000011100101 |
3 | 112100012221120111220121 |
4 | 2023231231230003211 |
5 | 4424213332041224 |
6 | 152530014201541 |
7 | 13560364004665 |
oct | 2135555540345 |
9 | 470187514817 |
10 | 150017065189 |
11 | 586927a4512 |
12 | 250a84b32b1 |
13 | 111b9c75ac4 |
14 | 7391b541a5 |
15 | 3d80350be4 |
hex | 22edb6c0e5 |
150017065189 has 4 divisors (see below), whose sum is σ = 150412888960. Its totient is φ = 149621241420.
The previous prime is 150017065153. The next prime is 150017065193. The reversal of 150017065189 is 981560710051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 150017065189 - 215 = 150017032421 is a prime.
It is a super-3 number, since 3×1500170651893 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150017065889) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197911317 + ... + 197912074.
It is an arithmetic number, because the mean of its divisors is an integer number (37603222240).
Almost surely, 2150017065189 is an apocalyptic number.
It is an amenable number.
150017065189 is a deficient number, since it is larger than the sum of its proper divisors (395823771).
150017065189 is an equidigital number, since it uses as much as digits as its factorization.
150017065189 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 395823770.
The product of its (nonzero) digits is 75600, while the sum is 43.
The spelling of 150017065189 in words is "one hundred fifty billion, seventeen million, sixty-five thousand, one hundred eighty-nine".
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