150032101120213 has 4 divisors (see below), whose sum is σ = 161573031975628. Its totient is φ = 138491170264800.

The previous prime is 150032101120169. The next prime is 150032101120241. The reversal of 150032101120213 is 312021101230051.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24429917531569 + 125602183588644 = 4942663^2 + 11207238^2 .

It is a cyclic number.

It is not a de Polignac number, because 150032101120213 - 2³³ = 150023511185621 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150032101120513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5770465427688 + ... + 5770465427713.

It is an arithmetic number, because the mean of its divisors is an integer number (40393257993907).

Almost surely, 2^{150032101120213} is an apocalyptic number.

150032101120213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

150032101120213 is a deficient number, since it is larger than the sum of its proper divisors (11540930855415).

150032101120213 is a wasteful number, since it uses less digits than its factorization.

150032101120213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11540930855414.

The product of its (nonzero) digits is 360, while the sum is 22.

Adding to 150032101120213 its reverse (312021101230051), we get a palindrome (462053202350264).

The spelling of 150032101120213 in words is "one hundred fifty trillion, thirty-two billion, one hundred one million, one hundred twenty thousand, two hundred thirteen".