Base | Representation |
---|---|
bin | 1000101110111010101… |
… | …1011001010101000011 |
3 | 112100021002000100111221 |
4 | 2023232223121111003 |
5 | 4424232002211121 |
6 | 152531353015511 |
7 | 13560651336664 |
oct | 2135653312503 |
9 | 470232010457 |
10 | 150033241411 |
11 | 586a0942999 |
12 | 250b19b4597 |
13 | 111c041a931 |
14 | 7393d6536b |
15 | 3d81998b41 |
hex | 22eead9543 |
150033241411 has 4 divisors (see below), whose sum is σ = 154873023424. Its totient is φ = 145193459400.
The previous prime is 150033241409. The next prime is 150033241417. The reversal of 150033241411 is 114142330051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150033241411 - 21 = 150033241409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (150033241417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2419890960 + ... + 2419891021.
It is an arithmetic number, because the mean of its divisors is an integer number (38718255856).
Almost surely, 2150033241411 is an apocalyptic number.
150033241411 is a deficient number, since it is larger than the sum of its proper divisors (4839782013).
150033241411 is an equidigital number, since it uses as much as digits as its factorization.
150033241411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4839782012.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 150033241411 its reverse (114142330051), we get a palindrome (264175571462).
The spelling of 150033241411 in words is "one hundred fifty billion, thirty-three million, two hundred forty-one thousand, four hundred eleven".
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