Base | Representation |
---|---|
bin | 1000101110111010111… |
… | …1110111011110111111 |
3 | 112100021011012220022202 |
4 | 2023232233313132333 |
5 | 4424232302213003 |
6 | 152531434102115 |
7 | 13560664321112 |
oct | 2135657673677 |
9 | 470234186282 |
10 | 150034413503 |
11 | 586a1573567 |
12 | 250b227a93b |
13 | 111c073b290 |
14 | 739418c579 |
15 | 3d81b2b088 |
hex | 22eebf77bf |
150034413503 has 16 divisors (see below), whose sum is σ = 163451211840. Its totient is φ = 136886720256.
The previous prime is 150034413469. The next prime is 150034413509. The reversal of 150034413503 is 305314430051.
It is not a de Polignac number, because 150034413503 - 28 = 150034413247 is a prime.
It is a super-3 number, since 3×1500344135033 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150034413509) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3317801 + ... + 3362717.
It is an arithmetic number, because the mean of its divisors is an integer number (10215700740).
Almost surely, 2150034413503 is an apocalyptic number.
150034413503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
150034413503 is a deficient number, since it is larger than the sum of its proper divisors (13416798337).
150034413503 is a wasteful number, since it uses less digits than its factorization.
150034413503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47906.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 150034413503 its reverse (305314430051), we get a palindrome (455348843554).
The spelling of 150034413503 in words is "one hundred fifty billion, thirty-four million, four hundred thirteen thousand, five hundred three".
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