Search a number
-
+
150034413503 = 1389288744917
BaseRepresentation
bin1000101110111010111…
…1110111011110111111
3112100021011012220022202
42023232233313132333
54424232302213003
6152531434102115
713560664321112
oct2135657673677
9470234186282
10150034413503
11586a1573567
12250b227a93b
13111c073b290
14739418c579
153d81b2b088
hex22eebf77bf

150034413503 has 16 divisors (see below), whose sum is σ = 163451211840. Its totient is φ = 136886720256.

The previous prime is 150034413469. The next prime is 150034413509. The reversal of 150034413503 is 305314430051.

It is not a de Polignac number, because 150034413503 - 28 = 150034413247 is a prime.

It is a super-3 number, since 3×1500344135033 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150034413509) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3317801 + ... + 3362717.

It is an arithmetic number, because the mean of its divisors is an integer number (10215700740).

Almost surely, 2150034413503 is an apocalyptic number.

150034413503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

150034413503 is a deficient number, since it is larger than the sum of its proper divisors (13416798337).

150034413503 is a wasteful number, since it uses less digits than its factorization.

150034413503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47906.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 150034413503 its reverse (305314430051), we get a palindrome (455348843554).

The spelling of 150034413503 in words is "one hundred fifty billion, thirty-four million, four hundred thirteen thousand, five hundred three".

Divisors: 1 13 89 1157 2887 37531 44917 256943 583921 3340259 3997613 51968969 129675379 1685779927 11541108731 150034413503