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150035340541 = 3473041142183
BaseRepresentation
bin1000101110111011001…
…1011001110011111101
3112100021012221222222111
42023232303121303331
54424233021344131
6152531510014021
713561005231622
oct2135663316375
9470235858874
10150035340541
11586a2047009
12250b2647311
13111c09a4218
147394350349
153d81c60ab1
hex22eecd9cfd

150035340541 has 8 divisors (see below), whose sum is σ = 150518257344. Its totient is φ = 149552714880.

The previous prime is 150035340529. The next prime is 150035340563. The reversal of 150035340541 is 145043530051.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150035340541 is a prime.

It is a super-2 number, since 2×1500353405412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150035340041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 984136 + ... + 1126318.

It is an arithmetic number, because the mean of its divisors is an integer number (18814782168).

Almost surely, 2150035340541 is an apocalyptic number.

It is an amenable number.

150035340541 is a deficient number, since it is larger than the sum of its proper divisors (482916803).

150035340541 is a wasteful number, since it uses less digits than its factorization.

150035340541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145571.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 150035340541 its reverse (145043530051), we get a palindrome (295078870592).

The spelling of 150035340541 in words is "one hundred fifty billion, thirty-five million, three hundred forty thousand, five hundred forty-one".

Divisors: 1 347 3041 142183 1055227 49337501 432378503 150035340541