150036726041 has 32 divisors (see below), whose sum is σ = 157050685440. Its totient is φ = 143226921600.

The previous prime is 150036726001. The next prime is 150036726043. The reversal of 150036726041 is 140627630051.

It is a cyclic number.

It is not a de Polignac number, because 150036726041 - 2¹⁴ = 150036709657 is a prime.

It is a super-3 number, since 3×150036726041³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 150036725992 and 150036726010.

It is not an unprimeable number, because it can be changed into a prime (150036726043) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 237775796 + ... + 237776426.

It is an arithmetic number, because the mean of its divisors is an integer number (4907833920).

Almost surely, 2^150036726041 is an apocalyptic number.

It is an amenable number.

150036726041 is a deficient number, since it is larger than the sum of its proper divisors (7013959399).

150036726041 is a wasteful number, since it uses less digits than its factorization.

150036726041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1317.

The product of its (nonzero) digits is 30240, while the sum is 35.

The spelling of 150036726041 in words is "one hundred fifty billion, thirty-six million, seven hundred twenty-six thousand, forty-one".