15004130535 has 12 divisors (see below), whose sum is σ = 26007159672. Its totient is φ = 8002202928.

The previous prime is 15004130513. The next prime is 15004130543. The reversal of 15004130535 is 53503140051.

It is not a de Polignac number, because 15004130535 - 2¹⁵ = 15004097767 is a prime.

It is a super-3 number, since 3×15004130535³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 15004130499 and 15004130508.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 166712517 + ... + 166712606.

It is an arithmetic number, because the mean of its divisors is an integer number (2167263306).

Almost surely, 2^15004130535 is an apocalyptic number.

15004130535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

15004130535 is a deficient number, since it is larger than the sum of its proper divisors (11003029137).

15004130535 is a wasteful number, since it uses less digits than its factorization.

15004130535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333425134 (or 333425131 counting only the distinct ones).

The product of its (nonzero) digits is 4500, while the sum is 27.

Adding to 15004130535 its reverse (53503140051), we get a palindrome (68507270586).

The spelling of 15004130535 in words is "fifteen billion, four million, one hundred thirty thousand, five hundred thirty-five".