150041531533 has 4 divisors (see below), whose sum is σ = 150045080220. Its totient is φ = 150037982848.

The previous prime is 150041531491. The next prime is 150041531551. The reversal of 150041531533 is 335135140051.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 335135140051 = 36307 ⋅9230593.

It can be written as a sum of positive squares in 2 ways, for example, as 94309181604 + 55732349929 = 307098^2 + 236077^2 .

It is a cyclic number.

It is not a de Polignac number, because 150041531533 - 2²⁹ = 149504660621 is a prime.

It is a super-2 number, since 2×150041531533² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150041531495 and 150041531504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150041532533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1710148 + ... + 1795741.

It is an arithmetic number, because the mean of its divisors is an integer number (37511270055).

Almost surely, 2^150041531533 is an apocalyptic number.

It is an amenable number.

150041531533 is a deficient number, since it is larger than the sum of its proper divisors (3548687).

150041531533 is an equidigital number, since it uses as much as digits as its factorization.

150041531533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3548686.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 150041531533 its reverse (335135140051), we get a palindrome (485176671584).

The spelling of 150041531533 in words is "one hundred fifty billion, forty-one million, five hundred thirty-one thousand, five hundred thirty-three".