Base | Representation |
---|---|
bin | 1000101110111110110… |
… | …0110100001111101111 |
3 | 112100022021021122100202 |
4 | 2023233230310033233 |
5 | 4424300400003043 |
6 | 152533204344115 |
7 | 13561250164601 |
oct | 2135754641757 |
9 | 470267248322 |
10 | 150050391023 |
11 | 586aa596725 |
12 | 250b76a503b |
13 | 111c3b43830 |
14 | 739634b171 |
15 | 3d832351b8 |
hex | 22efb343ef |
150050391023 has 4 divisors (see below), whose sum is σ = 161592728808. Its totient is φ = 138508053240.
The previous prime is 150050390951. The next prime is 150050391031. The reversal of 150050391023 is 320193050051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150050391023 - 226 = 149983282159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150050351023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5771168873 + ... + 5771168898.
It is an arithmetic number, because the mean of its divisors is an integer number (40398182202).
Almost surely, 2150050391023 is an apocalyptic number.
150050391023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
150050391023 is a deficient number, since it is larger than the sum of its proper divisors (11542337785).
150050391023 is a wasteful number, since it uses less digits than its factorization.
150050391023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11542337784.
The product of its (nonzero) digits is 4050, while the sum is 29.
The spelling of 150050391023 in words is "one hundred fifty billion, fifty million, three hundred ninety-one thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •