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15005421311 = 47309317179
BaseRepresentation
bin11011111100110010…
…01000111011111111
31102201202100101022212
431332121020323333
5221212341440221
610520550131035
71040563655666
oct157631107377
942652311285
1015005421311
116400195141
122aa9350a7b
1315519c682a
14a24c35ddd
155cc535b5b
hex37e648eff

15005421311 has 4 divisors (see below), whose sum is σ = 15005785800. Its totient is φ = 15005056824.

The previous prime is 15005421287. The next prime is 15005421313. The reversal of 15005421311 is 11312450051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 15005421311 - 214 = 15005404927 is a prime.

It is a super-2 number, since 2×150054213112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15005421313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111281 + ... + 205898.

It is an arithmetic number, because the mean of its divisors is an integer number (3751446450).

Almost surely, 215005421311 is an apocalyptic number.

15005421311 is a deficient number, since it is larger than the sum of its proper divisors (364489).

15005421311 is an equidigital number, since it uses as much as digits as its factorization.

15005421311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364488.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 15005421311 its reverse (11312450051), we get a palindrome (26317871362).

The spelling of 15005421311 in words is "fifteen billion, five million, four hundred twenty-one thousand, three hundred eleven".

Divisors: 1 47309 317179 15005421311