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150054444401 = 839178849159
BaseRepresentation
bin1000101110111111110…
…0010001110101110001
3112100022112220120112212
42023233330101311301
54424302414210101
6152533431301505
713561326506201
oct2135774216561
9470275816485
10150054444401
1158701905024
12250b8b1a895
13111c4932794
147396ac4401
153d837861bb
hex22eff11d71

150054444401 has 4 divisors (see below), whose sum is σ = 150233294400. Its totient is φ = 149875594404.

The previous prime is 150054444389. The next prime is 150054444433. The reversal of 150054444401 is 104444450051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104444450051 = 412547425611.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150054444401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150054444451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89423741 + ... + 89425418.

It is an arithmetic number, because the mean of its divisors is an integer number (37558323600).

Almost surely, 2150054444401 is an apocalyptic number.

It is an amenable number.

150054444401 is a deficient number, since it is larger than the sum of its proper divisors (178849999).

150054444401 is an equidigital number, since it uses as much as digits as its factorization.

150054444401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178849998.

The product of its (nonzero) digits is 25600, while the sum is 32.

Adding to 150054444401 its reverse (104444450051), we get a palindrome (254498894452).

The spelling of 150054444401 in words is "one hundred fifty billion, fifty-four million, four hundred forty-four thousand, four hundred one".

Divisors: 1 839 178849159 150054444401