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150131422123303 = 194585977154317
BaseRepresentation
bin100010001000101100110010…
…000101011101010100100111
3201200120102102221101101110211
4202020230302011131110213
5124134223123030421203
61251145231224200251
743423431411314665
oct4210546205352447
9650512387341424
10150131422123303
1143922418963705
1214a08585609087
1365a0442266c0a
142910584715c35
1512553e2057c6d
hex888b3215d527

150131422123303 has 4 divisors (see below), whose sum is σ = 150131501223480. Its totient is φ = 150131343023128.

The previous prime is 150131422123301. The next prime is 150131422123313. The reversal of 150131422123303 is 303321224131051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150131422123303 - 21 = 150131422123301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150131422123301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36631300 + ... + 40523017.

It is an arithmetic number, because the mean of its divisors is an integer number (37532875305870).

Almost surely, 2150131422123303 is an apocalyptic number.

150131422123303 is a deficient number, since it is larger than the sum of its proper divisors (79100177).

150131422123303 is an equidigital number, since it uses as much as digits as its factorization.

150131422123303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79100176.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 150131422123303 its reverse (303321224131051), we get a palindrome (453452646254354).

The spelling of 150131422123303 in words is "one hundred fifty trillion, one hundred thirty-one billion, four hundred twenty-two million, one hundred twenty-three thousand, three hundred three".

Divisors: 1 1945859 77154317 150131422123303