150243111703 has 4 divisors (see below), whose sum is σ = 150245957160. Its totient is φ = 150240266248.

The previous prime is 150243111671. The next prime is 150243111709. The reversal of 150243111703 is 307111342051.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 307111342051 = 42157 ⋅7284943.

It is a cyclic number.

It is not a de Polignac number, because 150243111703 - 2⁵ = 150243111671 is a prime.

It is a super-2 number, since 2×150243111703² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150243111709) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342000 + ... + 1449637.

It is an arithmetic number, because the mean of its divisors is an integer number (37561489290).

Almost surely, 2^150243111703 is an apocalyptic number.

150243111703 is a deficient number, since it is larger than the sum of its proper divisors (2845457).

150243111703 is an equidigital number, since it uses as much as digits as its factorization.

150243111703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2845456.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 150243111703 its reverse (307111342051), we get a palindrome (457354453754).

The spelling of 150243111703 in words is "one hundred fifty billion, two hundred forty-three million, one hundred eleven thousand, seven hundred three".