Base | Representation |
---|---|
bin | 100010001010011011001110… |
… | …000011110000011110000111 |
3 | 201200222202112001022002211102 |
4 | 202022123032003300132013 |
5 | 124143144001234241020 |
6 | 1251315522024530315 |
7 | 43435130066424455 |
oct | 4212331603603607 |
9 | 650882461262742 |
10 | 150250003040135 |
11 | 43968739785619 |
12 | 14a2755a02099b |
13 | 65ab68c4507ab |
14 | 29161d33bd9d5 |
15 | 1258532649475 |
hex | 88a6ce0f0787 |
150250003040135 has 4 divisors (see below), whose sum is σ = 180300003648168. Its totient is φ = 120200002432104.
The previous prime is 150250003040129. The next prime is 150250003040191. The reversal of 150250003040135 is 531040300052051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150250003040135 - 240 = 149150491412359 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 150250003040098 and 150250003040107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15025000304009 + ... + 15025000304018.
It is an arithmetic number, because the mean of its divisors is an integer number (45075000912042).
Almost surely, 2150250003040135 is an apocalyptic number.
150250003040135 is a deficient number, since it is larger than the sum of its proper divisors (30050000608033).
150250003040135 is an equidigital number, since it uses as much as digits as its factorization.
150250003040135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30050000608032.
The product of its (nonzero) digits is 9000, while the sum is 29.
Adding to 150250003040135 its reverse (531040300052051), we get a palindrome (681290303092186).
The spelling of 150250003040135 in words is "one hundred fifty trillion, two hundred fifty billion, three million, forty thousand, one hundred thirty-five".
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