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150312243143 = 297809504727
BaseRepresentation
bin1000101111111101001…
…1101100111111000111
3112100222112000002221102
42023333103230333013
54430314413240033
6153015201010315
713600606662056
oct2137723547707
9470875002842
10150312243143
1158824385037
122516b32399b
1311236175b0a
1473bd03039d
153d9b20ade8
hex22ff4ecfc7

150312243143 has 4 divisors (see below), whose sum is σ = 150313045680. Its totient is φ = 150311440608.

The previous prime is 150312243097. The next prime is 150312243157. The reversal of 150312243143 is 341342213051.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 150312243143 - 212 = 150312239047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150312243043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45446 + ... + 550172.

It is an arithmetic number, because the mean of its divisors is an integer number (37578261420).

Almost surely, 2150312243143 is an apocalyptic number.

150312243143 is a deficient number, since it is larger than the sum of its proper divisors (802537).

150312243143 is an equidigital number, since it uses as much as digits as its factorization.

150312243143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802536.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 150312243143 its reverse (341342213051), we get a palindrome (491654456194).

The spelling of 150312243143 in words is "one hundred fifty billion, three hundred twelve million, two hundred forty-three thousand, one hundred forty-three".

Divisors: 1 297809 504727 150312243143