Search a number
-
+
150403101 = 350134367
BaseRepresentation
bin10001111011011…
…11100000011101
3101111000021021020
420331233200131
5302000344401
622531354353
73504256002
oct1075574035
9344007236
10150403101
1177998092
12424529b9
1325210524
1415d918a9
15d30dd36
hex8f6f81d

150403101 has 4 divisors (see below), whose sum is σ = 200537472. Its totient is φ = 100268732.

The previous prime is 150403093. The next prime is 150403111. The reversal of 150403101 is 101304051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 150403101 - 23 = 150403093 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150403111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25067181 + ... + 25067186.

It is an arithmetic number, because the mean of its divisors is an integer number (50134368).

Almost surely, 2150403101 is an apocalyptic number.

It is an amenable number.

150403101 is a deficient number, since it is larger than the sum of its proper divisors (50134371).

150403101 is an equidigital number, since it uses as much as digits as its factorization.

150403101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50134370.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 150403101 is about 12263.8942020877. The cubic root of 150403101 is about 531.8048130230.

Adding to 150403101 its reverse (101304051), we get a palindrome (251707152).

The spelling of 150403101 in words is "one hundred fifty million, four hundred three thousand, one hundred one".

Divisors: 1 3 50134367 150403101