15041141414113 has 4 divisors (see below), whose sum is σ = 15324936535188. Its totient is φ = 14757346293040.

The previous prime is 15041141414099. The next prime is 15041141414149. The reversal of 15041141414113 is 31141414114051.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13237430635584 + 1803710778529 = 3638328^2 + 1343023^2 .

It is a cyclic number.

It is not a de Polignac number, because 15041141414113 - 2¹³ = 15041141405921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15041141411113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141897560458 + ... + 141897560563.

It is an arithmetic number, because the mean of its divisors is an integer number (3831234133797).

Almost surely, 2^{15041141414113} is an apocalyptic number.

It is an amenable number.

15041141414113 is a deficient number, since it is larger than the sum of its proper divisors (283795121075).

15041141414113 is an equidigital number, since it uses as much as digits as its factorization.

15041141414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283795121074.

The product of its (nonzero) digits is 3840, while the sum is 31.

Adding to 15041141414113 its reverse (31141414114051), we get a palindrome (46182555528164).

The spelling of 15041141414113 in words is "fifteen trillion, forty-one billion, one hundred forty-one million, four hundred fourteen thousand, one hundred thirteen".