Base | Representation |
---|---|
bin | 1000110000011010000… |
… | …1101000001100100011 |
3 | 112101021221212011102212 |
4 | 2030012201220030203 |
5 | 4431041413142201 |
6 | 153035204232335 |
7 | 13603610145560 |
oct | 2140641501443 |
9 | 471257764385 |
10 | 150433334051 |
11 | 58886771470 |
12 | 251a399b6ab |
13 | 11255292440 |
14 | 73d1151867 |
15 | 3da6b79abb |
hex | 2306868323 |
150433334051 has 32 divisors (see below), whose sum is σ = 203980363776. Its totient is φ = 107132400000.
The previous prime is 150433334041. The next prime is 150433334071.
150433334051 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 150433334051 - 218 = 150433071907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 150433333999 and 150433334017.
It is not an unprimeable number, because it can be changed into a prime (150433334041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 642875 + ... + 845076.
It is an arithmetic number, because the mean of its divisors is an integer number (6374386368).
Almost surely, 2150433334051 is an apocalyptic number.
150433334051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
150433334051 is a deficient number, since it is larger than the sum of its proper divisors (53547029725).
150433334051 is a wasteful number, since it uses less digits than its factorization.
150433334051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1488083.
The product of its (nonzero) digits is 32400, while the sum is 32.
It can be divided in two parts, 150433 and 334051, that added together give a palindrome (484484).
The spelling of 150433334051 in words is "one hundred fifty billion, four hundred thirty-three million, three hundred thirty-four thousand, fifty-one".
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